Why is the Berkovich spectrum of a C*-Algebra the same as the Gelfand spectrum?

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http://ift.tt/eA8V8J

Now view A A as a normed algebra over C C with respect to the supremum norm ∥a∥sup=supx∈X(∥a(x)∥) ∥ a ∥ s u p = sup x ∈ X ( ∥ a ( x ) ∥ ) ...

from Algebra

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